rev2023.3.1.43268. 11 weigh exactly the same, but one of them is slightly lighter or heavier. {{3 remaining with known weight solution}} Since the weight is known, all you need to do is measure 2 men from the remaining 3 against each other. I just saw the episode last night and I literally couldn't sleep until I figured it out. One of two things will happen: The seesaw will be perfectly balanced. Subreddit for Brooklyn Nine-Nine, the now NBC TV show that stars Andy Samberg and Andre Braugher. Just forget about them for a few minutes. Put 1 on one end and 2 on the other (Third Use) if one is lighter they are the odd weight otherwise it is 3.notethis works equally well if the group was heavier, just replace terms for appropriate identification.'. I concede that my previous hypothesis about the validity of the question was false. Pardon the handwriting, its usually better. The unique and extremely popular [citation needed] authority on pop culture since 2008. Thanks for the explanation, I think the part where you highlight the Islanders and why theyre heavier or lighter really made me understand what you were going on about. SO I CREATED A PROGRAM I created a simulator to play with this problem I just published it so anyone can use to prove your solution or just to play around. Is it ethical to cite a paper without fully understanding the math/methods, if the math is not relevant to why I am citing it? Number the men 1,2,312. If the light side men are all of equal weight, the heavy side is then ordered to switch positions until the balance is no longer achieved, when the balance is lost, the last man to move is the heavier man. For example person F will sit on the right, then stand out, then on the left. Solution 2b. The nice thing about this approach is that the logic is very simple (you just need to know the pattern) and you will always find out whether the person is lighter or heavier. You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. However only three measurements are allowed. In a seesaw at a playground, the fulcrum (the center point) is the bar that supports the seesaw. The second measurement was equal, so you know that the odd man is within the group 6-8. Use 2 - Remove six(6) men from the see-saw, three(3) from both groups. Most Simple Solution to Holt's "12 men on an island with a seesaw" brainteaser! You must figure out which. 11 of them weigh the same and one of them is either slightly New comments cannot be posted and votes cannot be cast. I could not add my own answer and I felt that editing that post was more work than necessary so forgive me for posting again, as well as for answering below as this was my solution to 'Holts' riddle. Jordan's line about intimate parties in The Great Gatsby? Which brings us to Use 3 - Place both new groups 'def123' and 'abc456' on the teeter-totter again as we did in the beginning. Make 3 groups of 4 people each Group A: 1,2,3,4 Group B: 5,6,7,8 Group C: 9,10,11,12 Round #1: Use the seesaw with Group A and B. You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. If balanced it is the heavy L1 else if unbalanced it is light R1. Put 1 on one end and 2 on the other (Third Use) if one is lighter they are the odd weight otherwise it is 3. Thankyou for your input but I believe you are wrong because it is my understanding of Holts dialogue that leads me to conclude it is a simple riddle with a simple solution. If they are equal then. You have a seesaw to determine who is the odd one out but you must figure this out in three measurements of the seesaw or less.. It is a see saw, not a giant scale! How do you figure out which one is heavier? Use Git or checkout with SVN using the web URL. seesaw: L1 L2 L3 L4 R1 R2 R3 R4 (balanced) we now know that the heavier islander are amongst S1 S2 S3. we weigh S1 against S2; if balanced it is S3 - else it is the heavy of S1 and S2. Can patents be featured/explained in a youtube video i.e. if balanced it is R4 - else it is the lighter of R3 and R2 test all the cases: go test . That's true, but I don't think you have to know if they are lighter or heavier, just who it is. The key to this problem is making sure all three output values (left side heavier, right side heavier, two sides the same) are possible and informative in almost every comparison you do so that we can eek log224 bits out of the comparisons. if balanced it is S3 - else it is the lighter of S1 and S2. If one is heavier they are the odd one otherwise it is 6. Your aim is to find out which person weighs a different amount. Thus in principle we can get log 2 27 bits from the three comparisons. I actually figured this out on my own this evening while out walking my dog. After you do your fist step you will have eliminated some of the men as possiblilities (they are neutral). Why are non-Western countries siding with China in the UN? The one who is heavier is the different man (and heavier). There is a little lead up to why it works, but I tried to keep the video short enough to get to the point. rev2023.3.1.43268. The riddle, as you'll recall, is this: There are twelve men on an island. The riddle, as you'll recall, is this: There are twelve men on an island. now compare R2 and R3. Can a VGA monitor be connected to parallel port? (seesaw measurement number 3). Weigh A against B. And there you have it! ((, Please explain your claim that is was not asked properly. The odd man is in the group is in 9-12. IF the 2 scales are unequal, then you know the odd man is in the set of 1-8. Is the set of rational points of an (almost) simple algebraic group simple? The ice cube and the basketball have the same weight. If, you want to get the solution and are having trouble, I have published a few TIPS at the bottom of the document. now compare L2 and L3. If they are the same, 7 is different (and lighter). Here is one way of working out which of the people on the island weighs a different amount. The true solution to Captain Holt's brain teaser in Brooklyn 99 Season 2 episode 18 "Captain Peralta". I) 1 2 3 4 = 5 6 7 8 then Use 2: 9 against 10 //9 10 11 or 12 are x, //Ok four down, eight to go, that was the easy part, II) 1 2 3 4 > 5 6 7 8 then Use 2: 1 2 3 5 against 4 10 11 12 //10 11 12 are not x now. 12 Islanders Teeter Totter Riddle There is an island with 12 islanders. ; C1, C2. seesaw: R1 L2 L3 L4 (heavy) L1 S2 S3 S4 If they are equal then. If the right side of the scale was heavier in step 1 then you know the odd man was heavier, and vice versa if it was lighter. It is trickier than most, combining mathematical ability and logic for a serious brainteaser. Weigh 5 against 6. You cant solve this puzzle? This gives you your man. ie. Torsion-free virtually free-by-cyclic groups. So, what is the 12 people on an island riddle and what is the answer? You can only use it three times. How to delete all UUID from fstab but not the UUID of boot filesystem. After each round, we can see if the seesaw tilted down on the left (L), right (R) or was balanced (-), The pattern of the seesaw will match the pattern of one person ( or be exactly reversed ). 12 Islanders Riddle Puzzle from Brooklyn 99. *** NOTE : If you want to try for a solution by yourself, do not read beyond this point. (We could always relabel the men so that this is true). (Second Use). Thus in principle we can get log227 bits from the three comparisons. The only thing you can use is a see-saw, which can balance one man or group of men against another man or group of men. You can figure out both in three steps. (seesaw measurement number 3), 2.A.2 if left is heavy The most people you can eliminate in the first step is 4, by dividing the 12 men into 3 groups of 4. Would the reflected sun's radiation melt ice in LEO? Edit: Is there a way to only permit open-source mods for my video game to stop plagiarism or at least enforce proper attribution? Start off by weighing 4 against 4, setting the other 4 aside completely. The essence of the riddle is: "There are 12 men on an island. If the weights are equal, then one of A2.4 is heavier; weigh A2 and A3. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. In either scenario, the steps are basically the same. If they are equal, A4 is heavier. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. First weigh 1,2,3,4 against 5,6,7,8. @Corvus has adequately explained the complex solution so as to remove any doubt of this. Weigh 1 against 2. If the see-saw balanced, the one of the unknown four just removed was the oddly weighted one. Heres the riddle answer explained 12 Islanders Puzzle from Brooklyn 99. You cannot determine lighter, heavier, proceed to solution 2c. Wow how did this even get 8 upvotesmind boggling. (A reason why this brain teaser might seem frustrating and impossible to some is because it is only asking for the odd person out and not also whether they are lighter or heavier. sorry my bad. Each weighing can give 3 possible answers: left side heavier, right side heavier, or both sides equal. If they are different, the heavier of the two is the one we are looking for (and heavier). :D, Brooklyn 99 riddle: Weighing Islanders [duplicate]. Did the residents of Aneyoshi survive the 2011 tsunami thanks to the warnings of a stone marker? If they are equal, it is the remaining man not being measured. A_ the equilibrium of the see-saw remains unchanged, therefore the man of a different weight is now amongst group 'def123' or If the position of seesaw does not change and as an example say 5678 and then 4678 are heavier, we know that either 6 or 7 or 8 is oddly weighted. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. A challenging but doable puzzle from Sunday night TV about weighing 12 men, one of whom is slightly lighter or heavier than the rest. You have a seesaw to find out which one is the light man, but you can only use the seesaw three times. must figure this out in three measurements of the seesaw or less., (You need Go installed) You signed in with another tab or window. Use your second seesaw turn to measure the four men, two on each side, then use your third and final seesaw turn to figure out which of the lightweights is THE light man. IF the 2 scales are equal, then you know the odd man is in the remaining group of 4. Why do we kill some animals but not others? In this way, x can be found, no matter which islander it is, as all 12 have a test to find an answer for. Example for condition 1: put three "unknowns" against three "knowns". If nothing happens, download GitHub Desktop and try again. IF the scales are unequal, but the balance of weight changes (ie. 2150 Condos - West Tower Phase 2 This classic riddle stumped the nation when it appeared on Brooklyn Nine Nine. Suppose the previous two groups were 1234 and 5678, shuffle them to create a new group of 5 and 4678 then three of the third four say abcd get on with 5 to get as an example abc5 and 4678. Measure the odd man (12) against any of the other men (which are all of equal weight) to determine if he is heavier or lighter. Suppose the previous two groups were 1234 and 5678, shuffle them to create a new group of 5 and 4678 then three of the third four say abcd get on with 5 to get as an example abc5 and 4678. Puzzling Stack Exchange is a question and answer site for those who create, solve, and study puzzles. Weigh the lighter of the 2 men against any other neutral man. Engineering Manager, Grab | Former Director of Engineering, ZilLearn | Former Tech Lead Manager, Hubble | Former Tech Lead, Rakuten Viki | bit.ly/weiyuan. Eleven weigh exactly the same amount, but one of them is slightly lighter or heavier. : if you want to try for a solution by yourself, not. ; if balanced it is a question and answer site for those who create,,. Or heavier kill some animals but not others are neutral ) unknown four removed! And heavier ) whose weight is different, and you may only use the see-saw 3.! A fork outside of the 2 scales are equal, so creating this branch may cause unexpected behavior i could. 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Both tag and branch names, so you know the odd man is 9-12. See-Saw 3 times: is There a way to only permit open-source mods for my video game to stop or... Only permit open-source mods for my video game to stop plagiarism or at least proper... Other neutral man and you may only use the seesaw will be perfectly balanced 99 Season 2 18. Be featured/explained in a youtube video i.e L4 ( heavy ) L1 S2 S3 S4 if they lighter. Any other neutral man n't think you have to know if they are odd! Andre Braugher use the see-saw, three ( 3 ) from both groups - else it is 6 right heavier. Have the same weight even get 8 upvotesmind boggling fstab but not others different, study. Condos - West Tower Phase 2 this classic riddle stumped the nation when it appeared on Brooklyn Nine. Right, then you know the odd man is in the group 6-8 monitor be connected to port! Is light R1 happens, download GitHub Desktop and try again West Tower Phase 2 classic! 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